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Armstrong Number Try It 🔻
using namespace std;
int main()
{
int arm=0,a,d,no;
cout<<"Enter any Number : ";
cin>>no;
d=no;
while(no>0)
{
a=no%10;
no=no/10;
arm=arm+a*a*a;
}
if(arm==d)
{
cout<<"\nGiven Number "<<d<<" is Armstrong";
}
else
{
cout<<"\nGiven Number "<<d<<" is not Armstrong";
}
return 0;
}
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OUTPUT Try It 🔻
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Enter any Number : 121
Given Number 121 is not Armstrong
//Run Again
Enter any Number : 153
Given Number 153 is Armstrong